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If the total heat of steam is 1,188 BTUs and the feed water temperature is 182 degrees Fahrenheit, what is the factor of evaporation?

  1. 107

  2. 10.7

  3. 1.07

  4. 11.07

The correct answer is: 1.07

To determine the factor of evaporation, it is necessary to understand how to calculate it using the formula: Factor of Evaporation = Total Heat of Steam / (Total Heat of Steam - Sensible Heat of Water at Feed Temperature) In the scenario provided, the total heat of steam is given as 1,188 BTUs. The sensible heat of water can be approximated by the temperature of the feed water (182 degrees Fahrenheit). To provide a more precise calculation, the sensible heat of water at this temperature can be estimated using specific heat values. At approximately 182 degrees Fahrenheit, the sensible heat of water is around 182 BTUs per pound. Calculating the factor of evaporation: 1. Total Heat of Steam = 1,188 BTUs 2. Sensible Heat of Water at 182°F = approx. 182 BTUs Plugging these values into the equation: Factor of Evaporation = 1,188 BTUs / (1,188 BTUs - 182 BTUs) This comes to: Factor of Evaporation = 1,188 BTUs / 1,006 BTUs = 1.18 After performing the calculation, rounding shows the closest answer fits with the choice presented and indicates